Einstein’s General Relativity

Derivations, Applications and Reflections – by Albert Prins

Appendix 4 – The Schwarzschild Formula Extended for Electric Charges

Reissner–Nordström Metric

The correct solution within general relativity for a charged, non-rotating, spherically symmetric mass is the Reissner–Nordström metric (1918). This metric describes the spacetime interval around a charged mass and incorporates both the gravitational and the electrical contributions:

\[ ds^{2} = c^{2} d\tau^{2} = \left( 1 - \frac{2GM}{c^{2} r} + \frac{GQ^{2}}{4\pi\varepsilon_{0} c^{4} r^{2}} \right) c^{2} dt^{2} - \left( 1 - \frac{2GM}{c^{2} r} + \frac{GQ^{2}}{4\pi\varepsilon_{0} c^{4} r^{2}} \right)^{-1} dr^{2} \] \[ - r^{2} d\theta^{2} - r^{2} \sin^{2}\theta\, d\phi^{2} \]

or

\[ ds^{2} = c^{2} d\tau^{2} = \left( 1 - \frac{r_{s}}{r} + \frac{r_{Q}^{2}}{r^{2}} \right) c^{2} dt^{2} - \left( 1 - \frac{r_{s}}{r} + \frac{r_{Q}^{2}}{r^{2}} \right)^{-1} dr^{2} \] \[ - r^{2} d\theta^{2} - r^{2} \sin^{2}\theta\, d\phi^{2} \]

where:

Interpretation

In classical Newtonian physics there exists a gravitational field in the vacuum. According to Einstein, however, there is no gravitational field as such; instead spacetime itself is curved due to gravitation. In that case, \( T_{\mu\nu} = 0 \).

In the case of the Reissner–Nordström solution, the stress–energy tensor \( T_{\mu\nu} \) is not zero everywhere, even though one speaks of a “vacuum.”

Explanation

In summary: in the Reissner–Nordström metric, \( T_{\mu\nu} \neq 0 \) in the “vacuum” because the electromagnetic field of the charge is physically real and contains energy.

Derivation of the Reissner–Nordström Metric

Below follows a step-by-step derivation of the Reissner–Nordström metric starting from the Einstein–Maxwell equations. This is the standard procedure in general relativity for determining the spacetime of a spherically symmetric, charged mass.

Step 1: Assumptions — metric and source

We seek a static, spherically symmetric solution of the form (spherical coordinates):

\[ ds^{2} = c^{2} d\tau^{2} = A(r)\, c^{2} dt^{2} - B(r)\, dr^{2} - r^{2} d\theta^{2} - r^{2} \sin^{2}\theta\, d\phi^{2} \]

where \( A(r) \) and \( B(r) \) are unknown functions of the radius \( r \).

Here:

For the four-potential we take:

\[ A_{\mu} = \left( \frac{\Phi}{c},\, -\mathbf{A} \right) \quad \text{or} \quad A^{\mu} = \left( \frac{\Phi}{c},\, \mathbf{A} \right) \]

The Electromagnetic Field Tensor

The electromagnetic field tensor \( F_{\mu\nu} \) contains all information about the electric field \( \mathbf{E} \) and the magnetic field \( \mathbf{B} \).

In matrix form:

\[ F_{\mu\nu} = \begin{pmatrix} 0 & -E_{x}/c & -E_{y}/c & -E_{z}/c \\ E_{x}/c & 0 & -B_{z} & B_{y} \\ E_{y}/c & B_{z} & 0 & -B_{x} \\ E_{z}/c & -B_{y} & B_{x} & 0 \end{pmatrix} \]

For a purely radial electric field of a point charge \( Q \), this becomes:

\[ F_{\mu\nu} = \begin{pmatrix} 0 & \frac{Q}{r^{2}} & 0 & 0 \\ -\frac{Q}{r^{2}} & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \\ 0 & 0 & 0 & 0 \end{pmatrix} \]

The only non-zero component of \( F_{\mu\nu} \) in this radial field is:

\[ F_{tr} = -F_{rt} = \frac{Q}{r^{2}} \]

Step 2: Einstein–Maxwell Equations

The Einstein equation with an electromagnetic source is:

\[ G_{\mu\nu} = 8\pi\, T_{\mu\nu} \]

where \( G_{\mu\nu} \) is the Einstein tensor of the metric.

The Maxwell equations in vacuum are:

\[ \nabla_{\mu} F^{\mu\nu} = 0, \qquad \nabla_{[\alpha} F_{\beta\gamma]} = 0 \]

For the static, spherically symmetric situation this yields:

\[ F^{tr} = \frac{Q}{r^{2}} \sqrt{\frac{1}{A(r) B(r)}} \]

Step 3: Computing the Einstein Tensor

The Einstein tensor components for the general metric \[ ds^{2} = A(r)c^{2}dt^{2} - B(r)dr^{2} - r^{2}d\theta^{2} - r^{2}\sin^{2}\theta\, d\phi^{2} \] are:

\[ G_t^t = \frac{B'}{r B^{2}} + \frac{1}{r^{2}}\left(1 - \frac{1}{B}\right) \] \[ G_r^r = \frac{A'}{r A B} - \frac{1}{r^{2}}\left(1 - \frac{1}{B}\right) \] \[ G_\theta^\theta = G_\phi^\phi = \frac{1}{4AB} \left( 2A'' - A' \frac{B'}{B} + \frac{A'^2}{A} \right) - \frac{1}{2rB} \left( \frac{A'}{A} - \frac{B'}{B} \right) \]

where a prime (′) denotes differentiation with respect to \( r \).

Step 4: Stress–Energy Tensor Components

The stress–energy tensor of the electric field is diagonal with:

\[ T_t^t = T_r^r = -\frac{Q^{2}}{8\pi r^{4}}, \qquad T_\theta^\theta = T_\phi^\phi = \frac{Q^{2}}{8\pi r^{4}} \]

Step 5: Coupling and Solving the Equations

The Einstein equations become explicitly:

\[ \frac{B'}{r B^{2}} + \frac{1}{r^{2}}\left(1 - \frac{1}{B}\right) = -\frac{Q^{2}}{r^{4}} \] \[ \frac{A'}{r A B} - \frac{1}{r^{2}}\left(1 - \frac{1}{B}\right) = -\frac{Q^{2}}{r^{4}} \]

Solving this system yields:

\[ A(r) = \frac{1}{B(r)} = 1 - \frac{2M}{r} + \frac{Q^{2}}{r^{2}} \]

where \( M \) is an integration constant representing the mass (in geometrized units).

Step 6: Result — Reissner–Nordström Metric

The solution is now the metric line element:

\[ ds^{2} = \left( 1 - \frac{2GM}{c^{2} r} + \frac{GQ^{2}}{4\pi\varepsilon_{0} c^{4} r^{2}} \right)c^{2} dt^{2} - \left( 1 - \frac{2GM}{c^{2} r} + \frac{GQ^{2}}{4\pi\varepsilon_{0} c^{4} r^{2}} \right)^{-1} dr^{2} - r^{2} d\Omega^{2} \]

where \[ d\Omega^{2} = d\theta^{2} + \sin^{2}\theta\, d\phi^{2}. \]

Conclusion

The Reissner–Nordström metric is the unique static, spherically symmetric solution of the Einstein–Maxwell equations with a point mass and electric charge. This means that both gravitational and electromagnetic interactions are incorporated into the spacetime description.

Remark on the cosmological constant

The classical Schwarzschild solution is an exact solution of Einstein’s field equations, but under the explicit assumption that the cosmological constant \( \lambda = 0 \). In the original Schwarzschild derivation, this \( \lambda \)-term is therefore neglected or omitted, meaning that the metric does not account for cosmological expansion or repulsion that would be caused by a non-zero \( \lambda \).

To what extent is \( \lambda \) included?

\[ ds^{2} = c^{2} d\tau^{2} = \left(1 - \frac{2GM}{c^{2} r}\right)c^{2} dt^{2} - \left(1 - \frac{2GM}{c^{2} r}\right)^{-1} dr^{2} - r^{2} d\theta^{2} - r^{2} \sin^{2}\theta\, d\phi^{2} \]

or …

Schwarzschild metric

\[ ds^{2} = c^{2} d\tau^{2} = \left(1 - \frac{r_{s}}{r}\right)c^{2} dt^{2} - \left(1 - \frac{r_{s}}{r}\right)^{-1} dr^{2} - r^{2} d\Omega^{2} \]

where \( r_{s} = \frac{2GM}{c^{2}} \) and \[ d\Omega^{2} = d\theta^{2} + \sin^{2}\theta\, d\phi^{2}. \]

Full Einstein equation

\[ R_{\mu\nu} - \frac{1}{2} R\, g_{\mu\nu} + \lambda g_{\mu\nu} = 8\pi T_{\mu\nu} \]

In the Schwarzschild derivation, \( \lambda = 0 \) is assumed (i.e. no cosmological constant).

If \( \lambda \neq 0 \): the Schwarzschild–de Sitter metric

When the \( \lambda \)-term is included, the Schwarzschild–de Sitter (or Kottler) metric arises:

\[ ds^{2} = \left(1 - \frac{r_{s}}{r} - \frac{\lambda r^{2}}{3}\right)c^{2} dt^{2} - \left(1 - \frac{r_{s}}{r} - \frac{\lambda r^{2}}{3}\right)^{-1} dr^{2} - r^{2} d\Omega^{2} \]

This is also an exact solution, but now explicitly includes the cosmological constant and describes, for example, a black hole in an expanding universe.

Conclusion

Thus: the classical Schwarzschild metric is exact, but only under the assumption that the cosmological constant plays no role.

Reissner–Nordström–de Sitter metric

When the Schwarzschild–de Sitter metric is combined with the Reissner–Nordström metric, the Reissner–Nordström–de Sitter solution emerges:

\[ ds^{2} = \left( 1 - \frac{2GM}{c^{2} r} + \frac{GQ^{2}}{4\pi\varepsilon_{0} c^{4} r^{2}} - \frac{\lambda r^{2}}{3} \right)c^{2} dt^{2} \] \[ - \left( 1 - \frac{2GM}{c^{2} r} + \frac{GQ^{2}}{4\pi\varepsilon_{0} c^{4} r^{2}} - \frac{\lambda r^{2}}{3} \right)^{-1} dr^{2} - r^{2} d\Omega^{2} \]

Explanation of the terms

Special cases